In American football, the ball is punted by dropping and kicking it before it hits the ground. The height h(t) of the football above the ground in meterst
seconds after being punted is affected by gravity and by the punter's kick,
and can be represented as the difference of two functions: a (t) 4.91",
which specifies the effect of gravity on the height of the ball, and v (t) 12.12 +2.5, which specifies the effect of the punt on the ba
With these two functions, h(t) == v(t) a(t), how high above the ground was the ball when it was punted?​

25.2

step-by-step explanation:

2+4x6-8/10= 25.2

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

their is no graph showing

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204