Two traffic lights operate independently. Your probability of being stopped at the first one is 0.4 and your probability of being stopped at the second one is 0.7. The probability at being stopped at the first light and second light is 0.3. What is your probability of being stopped at the first light or second light?Make sure to show your work. NEED HELP ASAP

Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.

There are three possibilities we need to consider:

Being stopped at both lights

Being stopped at neither light

Being stopped at exactly one light

The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.

Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28

The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18

Step-by-step explanation:

c) yes, because of asa or aas

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value