In the year 2020, the Santa Crust County approved budgets to construct a $32 million Highway 103. The construction will be financed by tax-supported bonds in the amounts of $30 million, and tax revenues. Please record journal entries for the following transactions for the capital project fund: 1. The county has issued a long-term $100,000, 6% bond anticipation notes to cover the planning costs. The notes will be repaid when the bond is issued.

2. The county has incurred engineering costs in the amount of $60,000.

3. The county entered into a construction contract of $32 million for this project.

4. The county issued the $30 million, 20-year 5 percent bonds at 101.

5. The county paid off the bond anticipation notes that had been outstanding 180 days.

6. The county was billed $16 million by the contractor. The county paid the balance less 5% retainage.

7. At the end of the year 2020, close all temporary accounts. Assume all fund balances are restricted.

8. In the year 2021, the construction contractor continued to work on the Highway and completed it in June 2021. The county was billed $14 million.

9. The county paid off the full balance, including the retainage, following a final inspection.

10. Highway 103 can be capitalized after the completion of the project.

Ihave trouble finding the nth term of a linear sequence

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.

Me i’m stuck on all these questions besides the two bottom ones