A line has a slope of 1
8
and passes through the point (
–
4,8). What is its equation in point-slope form?

Step 1. The General Equation of a straight line is

Y = Mx + C where

M is the slope and
C is that point on the y axis where the curve cuts that axis (where x = 0)
In this case we are told that M = (3/4)

Our equation is now Y = (3/4)X + C ••• Equ 1

We are told that this curve passes through Point ( x, y ) = ( 8, -1 ).

Substitute these values of x, and y into Equ 1 to find C.

Y = (3/4)X + C or

( -1 ) = ( 3/4 )*( 8 ) + C or

( -1 ) = ( 6 ) + C or

C = ( - 7 )

Therefore the Equation of the Point Slope curve is

Y = ( 3/4 )X - 7

: Hope this helps :)