(1 point) You wish to pack a cardboard box inside a wooden crate. In order to have room for the packing materials, you need to leave a 0.5 \ \mbox{ft} space around the front, back, and sides of the box, and a 1 \ \mbox{ft} space around the top and bottom of the box. If the cardboard box is x feet long, (x 3) feet wide, and (x-1) feet deep, find a formula in terms of x for the amount of packing material, M, needed. M(x)

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x

moderators are

n=1.75+1.75

step-by-step explanation:

3.5/2=1.75