A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 28 ​centimeters, and the length of the other leg is 22 centimeters. The student incorrectly says that the length of the hypotenuse is 7.1 centimeters. Answer parts a and b a. . Find the length of the hypotenuse of the right triangle to the nearest tenth of a centimeter. A. The length of the hypotenuse of the right triangle to the nearest tenth of a centimeter
b. What mistake might the student have​ made?
A.
she found the difference of the square roots of the lengths of the legs.
B.
she found the sum of the square roots of the lengths of the legs.
C.
she took the square root of the sum of the lengths of the legs.
D.
she took the square root of the difference of the lengths of the legs.
Click to select your answer and then click Check Answer.
​(Round to the nearest tenth as​ needed.)

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

1010: 3030

is it i think

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value