A ball is thrown into the air with an initial upward velocity of 48ft/s its height h in feet after t seconds is given by the function h=-16t^2 + 48t + 4 A. how many seconds will the ball reach its maximum height
B. what is the balls maximum height
C. what do you suppose would happen if the ball was thrown with less velocity would the number of seconds reach maximum height be higher or lower

answer: what are the following choices

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy

add 8+12 to get a simplified answer of 12r-20