If p(x) = 5(x^2 +1) + 16, what is the value of p(11)?
A. 622
B. 736
C. 626
D. 690​

C. p(11) = 626.

Step-by-step explanation:

Given  : p(x) = 5(x²+1)+16.

To find :  what is the value of p(11).

Solution : We have given  p(x) = 5(x²+1)+16.

For x = 11.

p(11) = 5((11)²+1)+16.

p(11) = 5 ( 121 + 1 ) +16.

p(11) = 5 (122) + 16.

p(11) =  610 + 16.

p(11) = 626.

Therefore,  p(11) = 626.

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

answer: 3 x 2 = 6 and 6+0

step-by-step explanation: sum equals addition and twice is multiplication so its

3 x 2 = 6

6+0= 6

identity property of zero