Write an equation of the line that passes through (2 -5) and is parallel to the line 2y=3x+10

A line parallel to 2y−3x=8 will have the same slope. We can determine the slope of the line 2y−3x=8 by transforming it into slope-intercept form.

2y−3x2yy=8=3x+8=32x+4

Since the equation y=32x+4 has the form y=mx+c, we see that the line 2x−3x=8 has slope 3/2.

Thus, the equation of the line parallel to 2y−3x=8 that passes through the point (−2,6) can be expressed in the form

y=32x+c

You can determine the value of c by substituting −2 for x and 6 for y.

Step-by-step explanation:

Given equation is

2y = 3x + 10

3x - 2y + 10 = 0 i)

Any line parallel to line I) is

3x - 2y + k = 0 ii)

As the line two passes through the point ( 2 , - 5 ) Now substituting the values

3 * 2 - 2 * ( - 5) + k = 0

6 + 10 + k = 0

16 + k = 0

k = - 16

Now putting the value of k in equation two

3x - 2y + 16 = 0 is the required equation.

Hope it will help :)❤

step-by-step explanation:

if u want da anser kill your teeser ifu hav wun