Mathematics, 23.04.2021 23:00 mashejaj
In the figure shown, \overset{\leftrightarrow }{CF}
CF
↔
intersects \overset{\leftrightarrow }{AD}
AD
↔
and \overset{\leftrightarrow }{EH}
EH
↔
at points BB and FF, respectively.
Part A
Given: \angle CBD\cong \angle BFE∠CBD≅∠BFE
Prove: \angle ABF\cong \angle BFE∠ABF≅∠BFE
Select from the drop-down menus to support each line of the proof.
Statement: \angle CBD\cong \angle BFE∠CBD≅∠BFE Reason:
Statement : \angle CBD\cong \angle ABF∠CBD≅∠ABF Reason:
Statement: \angle ABF\cong \angle BFE∠ABF≅∠BFE Reason:
Part B
Given: m\angle CBD=m\angle BFEm∠CBD=m∠BFE
Prove: m\angle BFE+m\angle DBF=180^{\circ}m∠BFE+m∠DBF=180
∘
Select from the drop-down menus to support each line of the proof.
Statement: m\angle CBD=m\angle BFEm∠CBD=m∠BFE Reason:
Statement: m\angle CBD+m\angle DBF=180^{\circ}m∠CBD+m∠DBF=180
∘
Reason:
Statement: m\angle BFE+m\angle DBF=180^{\circ}m∠BFE+m∠DBF=180
∘
Reason:
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In the figure shown, \overset{\leftrightarrow }{CF}
CF
↔
intersects \overset{\leftri...
↔
intersects \overset{\leftri...
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