A sample of size 168, taken from a normally distributed population whose standard deviation is known to be 8.60, has a sample mean of 80.60. Suppose that we have adopted the null hypothesis that the actual population mean is equal to 80, that is, H0 is that μ = 80 and we want to test the alternative hypothesis, H1, that μ ≠ 80, with level of significance α = 0.1. The upper limit of a 95% confidence interval for the population mean would equal:

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i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.

so then what are you asking?

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answer:   35 % is the probability of a late departure or an early arrival.

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let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

hey there : ) your answer would be a.

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