A) find, in ascending powers of X, the first 4 terms of the expansion (1+X)^7. B) Hence, find the coefficient of y^3 in the expansion of (1+y-y^2)^7.

Please help, this is mindbending. I understand (A) but not (B)​

homozygous. one is homozygous, while two is heterozygous.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

faster, im not sure why but i know it is faster