I'm not really sure if I'm getting this right. please correct me if I'm wrong​

D

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

   = πr² ×

   = π × 0.9² ×

   = 0.81π ×

   = 0.09π × 2

   = 0.18π in² → D

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

i think it is 70

step-by-step explanation: