Help with this plz.
Solve the system of equations using the elimination method.​

Let's solve your system by elimination.

8x+y=−16;3x−y=5

8x+y=−16

3x−y=5

Add these equations to eliminate y:

11x=−11

Then solve: 11x=−11 for x:

11x=−11

11x

11

=

−11

11

(Divide both sides by 11)

x=−1

Now that we've found x let's plug it back in to solve for y.

Write down an original equation:

8x+y=−16

Substitute: −1 for x in 8x+y=−16:

(8)(−1)+y=−16

y−8=−16(Simplify both sides of the equation)

y−8+8=−16+8(Add 8 to both sides)

y=−8

x=−1 and y=−8

Multiply each equation by a suitable number so that the two equations have the same leading coefficient.

Subtract the second equation from the first.

Solve this new equation for y.

Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x.

Step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

c

step-by-step explanation: