plz hurry!! A person standing close to the edge on top of a 108-foot building throws a ball vertically upward. The quadratic function h ( t ) = − 16 t 2 + 132 t + 108 h ( t ) = - 16 t 2 + 132 t + 108 models the ball's height above the ground, h ( t ) h ( t ) , in feet, t t seconds after it was thrown. a) What is the maximum height of the ball?

The maximum height of the ball is 380.25 feet in the air.

Step-by-step explanation:

The quadratic function:

Models the ball's height h(t), in feet, above the ground t seconds after it was thrown.

We want to determine the maximum height of the ball.

Note that this is a quadratic function. Therefore, the maximum or minimum value will always occur at its vertex point.

Since our leading coefficient is leading, we have a maximum point. So to find the maximum height, we will find the vertex. The vertex of a quadratic equation is given by:

In this case, a = -16, b = 132, and c = 108. Find the t-coordinate of the vertex:

So, the maximum height occurs after 4.125 seconds of the ball being thrown.

To find the maximum height, substitute this value back into the equation. Thus:

The maximum height of the ball is 380.25 feet in the air.

the answer is 0.071

good luck! : d

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.