I have a square graph, but I would like to make the graph larger. The original side length is "s". The new side length is twice the original length plus 3.

Multiply the two side lengths to get the area of the new graph.

The area of the new graph is a perfect square trinomial: _ 3^2+_s+_

1,8,15,22,29,36,43,50

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7