A sales manager collected data on annual sales for new customer accounts and the number of years of experience for a sample of 10 salespersons. In the Microsoft Excel Online file below you will find a sample of data on years of experience of the salesperson and annual sales. Conduct a regression analysis to explore the relationship between these two variables and then answer the following questions. Open spreadsheet
Compute b1 and b0 (to 1 decimal).
b1 = fill in the blank
b0 = fill in the blank
Complete the estimated regression equation (to 1 decimal).
y= + x fill in the blank 5x
According to this model, what is the change in annual sales ($1000s) for every year of experience (to 1 decimal)?
fill in the blank
Compute the coefficient of determination (to 3 decimals). Note: report r2 between 0 and 1.
r2 = fill in the blank
What percentage of the variation in annual sales ($1000s) can be explained by the years of experience of the salesperson (to 1 decimal)?
fill in the blank %
A new salesperson joins the team with 8 years of experience. What is the estimated annual sales ($1000s) for the new salesperson (to the nearest whole number)?
$ fill in the blank
Salesperson Years of Experience Annual Sales ($1000s)
1 2 78
2 4 94
3 4 87
4 4 104
5 5 107
6 9 109
7 9 124
8 10 121
9 10 122
10 14 131

according to this law, when unemployment goes up by 1%, gdp drops by 2%. in the question, unemployment rate goes from 2% to 5%, meaning unemployment goes up by 3%, so the gdp drops by 6%. thus the effect is a drop in gdp by 6%.

step-by-step explanation:

step-by-step explanation:

if you want to separate 54 into 6 individual tiers then you need to divide if you want to separate 54 into 6 individual tiers then you need to divide 6 and 54.

if you divide 9 by 6 you will get 54.

- hope i .

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.