A rectangular pyramid has a height of 10 meters. The base measures 8 meters in length and 12 meters in width. Two different triangular cross sections are formed through the vertex and perpendicular to the base. What is the difference in the areas of the cross sections? Enter your answer in the box. m2
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The answer is  30 m²

Step-by-step explanation:

step 1

find the area of the first cross section

area1=b1*h/2

b1=8 m

h=10 m

area1=6*10/2> 30 m²

step 2

find the area of the second cross section

area 2=b2*h/2

b2=12 m

h=10 m

area1=12*10/2> 60 m²

step 3

find the difference in the areas of the cross sections

difference=60-30> 30 m²

area1=b1*h/2

b1=8 m

h=10 m

area1=6*10/2> 30 m²

area 2=b2*h/2

b2=12 m

h=10 m

area1=12*10/2> 60 m²

difference=60-30> 30 m²

30 m²

Step-by-step explanation: hope this helps

y = x + 95

y = 42 + 95

y=137 mm hg

heyyy

step-by-step explanation: