Sharina simplified the expression 3(2x – 6 – x + 1)2 – 2 + 4x. In Step 1 she simplified within the parentheses. In Step 2 she expanded the exponent. A table titled Sharina's Work with 1 column and 4 rows. The column is labeled 3(2 x minus 6 minus x + 1) squared minus 2 + 4 x. The first row has entry 3(x minus 5) squared minus 2 + 4 x. The second row has entry 3(x squared minus 10 x + 25) minus 2 + 4x. Rows 3 and 4 are blank.
Which is a possible next step?

Simplify the expression by adding and subtracting from left to right.
Combine like terms within the parentheses.
Combine all x-terms.
Distribute the 3 to each term in the parentheses by multiplying.

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< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)