Brand A and brand B of frozen green beans both list a weight of 32 ounces on their bags. Because of variability in the manufacturing process, the bags often contain slightly more, or less, than 32 ounces of green beans. An inspector takes a random sample of 25 bags of green beans of each type and records their weights. The weights and their relative frequencies are summarized in the histograms. 2 histograms comparing brand A and brand B of green beans. The median weight for brand B is less than the median weight of brand A. Which of the following is a true statement when comparing the bags of green beans? The median weight for both types is between 32.1 and 32.2 ounces. The median weight for both types is between 32.0 and 32.1 ounces. The median weight for brand B is less than the median weight of brand A. The median weight for brand B is greater than the median weight of brand A.

dont understand

step-by-step explanation:

46.2+112.3

step-by-step explanation:

answer:

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

explanation:

service only with 20% tip  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the  

service

−−−−−−  

so technically the answer is  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

however, the intention of the question provider may have been that your answer is to be  

$

87.12

(

1

+

8

100

)

=

$

94.09

to 2 decimal places.

'

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge  

.

→

$

72.60

20% tip  

20

100

×

$

72.60

=

$

14.52

−−−−−−  

←

add

$

87.12

tax  

8

100

×

$

87.12

=

$

6.97

−−−−−  

←

add

$

94.09

related questions

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°