The perimeter of a rectangle is (10x^2-6x+8). If the length of the rectangle is (3x^2-x-2), what is the width?

2(width) + 2(length) = perimeter

2(3x-3) + 2(length) = 10x+6

6x - 6 + 2(length) = 10x+6

2(length) = 4x + 12

length = 2x + 6

Brainliest would be greatly appreciated!

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

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