Janice has $2.46 worth of coins in her pocket. The coins are of four different denominations, and she has the same number of each denomination. What are the four denominations, and how many of each does she have?​

Solution #1:
If Janice has pennies, nickels, dimes, and quarters. Using trial and error, I found the following results:
1 of each coin: 0.01 + 0.05 + 0.10 + 0.25 = 0.41
2 of each coin: 0.02 + 0.10 + 0.20 + 0.50 = 0.82
3 of each coin: 0.03 + 0.15 + 0.30 + 0.75 = 1.23
4 of each coin: 0.04 + 0.20 + 0.40 + 1.00 = 1.64
5 of each coin: 0.05 + 0.25 + 0.50 + 1.25 = 2.05
6 of each coin: 0.06 + 0.30 + 0.60 + 1.50 = 2.46

Based upon these results, Janice has 6 of each coin.

Solution #2:
If we let x = the number of coins, then we can set up the equation
0.01x + 0.05x + 0.10x + 0.25x = 2.46 combine like terms
0.41x = 2.46 divide both sides of the equation by 0.41
x = 6

This confirms that Janice has 6 coins of each denomination including pennies, nickels, dimes and quarters.