Given
BAI BD
mZCBD = 40 +52
m ABC = 82 - 10°
Find mZCBD:
B
D

m∠CBD=68°

Step-by-step explanation:

BA is perpendicular to BD, meaning they form a right angle (90°)

This means m∠CBD + m∠ABC=90, or they are supplementary.

We have expressions given for these angles, so

4x+52+8x-10=90

12x+42=90

12x=48

x=4

Knowing x=4, we can substitute back into our expression for m∠CBD because that's what we're looking for.

4(4)+52=68

m∠CBD is 68°.

2

step-by-2step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐