ABCD is a quadrilateral inscribed in a circle, as shown below: Circle O is shown with a quadrilateral ABCD inscribed inside it. Angle A is labeled x plus 16. Angle B is labeled x degrees. Angle C is labeled 6x minus 4. Angle D is labeled 2x plus 16.

What equation can be used to solve for angle B?

(x + 16) − (6x − 4) = 180

(x + 16) + (x) = 90

(2x + 16) + (x) = 180

(x + 16) − (x) = 90

*I THINK ITS C*

any options?

step-by-step explanation:

i think it might be a but you might want a second opinion

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

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step-by-step explanation: