HELP PLEASE I HAVE BEEN STUCK FOR HOURS THIS IS DUE- I'll mark brainliest. In parallelogram WXYZ, diagonal WY is drawn, M and N are points on WX and YZ respectively, and WY intersects MN at E. If m<Z= 60°, m<WYX= 84°, and m<NEY= 102°, find m<ZNM. l'll mark brainliest, I'm not sure how to do this problem and I'm stressed-​

Opposite sides of the parallelogram are equal. Here, 60°+60°+ Angle ZWX + Angle ZYX = 360°

or,2* Angle ZYX = 240° [ Angle ZWX = Angle ZYX]

So, Angle ZYX = 120°

Then, In ∆ENY;

102° + (120-84)° + Angle ENY = 180° [Sum of all angles of a triangle.]

or, 36° + Angle ENY = 78°

So, Angle ENY = 42°

158

Step-by-step explanation:

to figure out ZNM you need to figure out what YNM is first. Once you know this you can use the linear pair to find ZNW

1st. in a parallelogram consecutive angles are supplementary. so WZN and XYN = 180

Since we know WZN is 60,  subtract from 180 and the XYN is 120

a part of XYN is 84, to find the angle measure of XYN 180-84=36

now us the triangle with angles 104 and 36 to find the value of MNY (180-102-36= 40

So MNY= 42

180-42= 158

Angle  ZNM- 158