If θ is an angle drawn in standard position with its terminal ray landing in the fourth quadrant and csc θ = -5, then what is the exact value of cos θ?

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000

answer: 34rtyj,jkhtyetwrhyjeuiejnbhdfknbkguxfrbhkfdbjvkmbd,kvbsd.kxjvbhjnfbgjxdfn

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)