the angle θ1\theta_1θ1​theta, start subscript, 1, end subscript is located in quadrant iii\text{iii}iiistart text, i, i, i, end text, and cos⁡(θ1)=−1315\cos(\theta_1)=-\dfra c{13}{15}cos(θ1​)=−1513​cosine, left parenthesis, theta, start subscript, 1, end subscript, right parenthesis, equals, minus, start fraction, 13, divided by, 15, end fraction . what is the value of sin⁡(θ1)\sin(\theta_1)sin(θ1​)sine, left parenthesis, theta, start subscript, 1, end subscript, right parenthesis

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!