Compute the value of the discriminant and give the number of real solutions of the Quadratic equation 3x^2+5x-2=0

Discriminant = 49, two real solutions

Step-by-step explanation:

Discriminant = b² - 4ac = (5)² - 4(3)(-2) = 25 + 24 = 49

Since 49>0, then the quadratic equation has two real solutions.

D=49  

x=1/3

x= -2

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

may i see the picture? it would a lot, xox