Point A is located at (-2, -3). After it is transformed, point A' is located at (-2, 3). How was the point transformed? A. it was reflected in the y-axis
B. it was rotated 180 degrees
C. it was rotated 90 degrees around the origin
D. it was reflected in the x-axis

i think u have 12 apples sorry again i don't really know if it correct i'm just tryna hrlp people out.

thus, the first answer choice, y = sec x, is the correct one

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0