Solve the following quadratic by
completing the square.
y = x2 + 4x - 2

x = √6 - 2 , -√6-2

Step-by-step explanation:

We have ,

=> y = x² + 4x - 2

=> x² + 4x - 2 = 0

=> x² + 2(2)(x) - 2 = 0

=> x² + 2(2)(x) +2² - 2² -2 = 0

=> x² + 2(2)(x) + 2² -4-2 = 0

=> ( x + 2 )² -6 = 0

=> ( x +2)² = 6

=> ( x + 2) = √6

=> x + 2 = ±√6

=> x = √6 - 2 , -√6-2

what is the original number? you forgot to add it.

me! what did you put for this question?

step-by-step explanation: