From the roof of a house the angle of depression of the top of a tree 20 ft. high was found to be 30°. If
the distance between the house and the tree is
10√2 find the height of the house.​

GB = CD = 20 ft, GC = BD = 10√3 ft, ∠FAC = 30°, AB = ? Or, AG = 10 ft. hence, the height of the house (AB) = 30 feet is the required answer.

final answer is : )

it would open into a square depending on the type of envelope i’m not sure about the second part