Mathematics, 02.05.2021 17:00 bvaughn6477

Sin^2A-cos^2B=sin2^B-cos^2A

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Sin^2A-cos^2B=sin2^B-cos^2A...

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Sin^2A-cos^2B=sin2^B-cos^2A​

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Sin^2A-cos^2B=sin2^B-cos^2A