Suppose that y varies jointly as x and Z and y = 6 when x = 5 and z = 2. What is the value of y when x = 4 and z = 3?

A)1.3
B)3.2
C)7.2
D)11.25

y=x/z

6=4/3

18/4

=4.5

when x=4,z=3

y=4/3

y=1.33

5050

hope this !

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?