Carolina is mowing the lawn for a summer job. For each cutting job, she charges an initial fee of $ 8 plus $ 6 for each hour of work. 1-Write an equation (in the form y = mx + b) to represent this problem. 2-If Carolina is paid a total of $ 32, how many hours did she work?

F(t) = 8 + 6(t)

Step-by-step explanation:

6*4 = 24

32-24 = 8

so her initial fee is $8

so function is:

F(t) = 8 + 6(t)

1. y = 6x + 8

2. 4 hours.

Step-by-step explanation:

x is each hour of work.

y is the total that Carolina is paid.

y = mx + b

32 = 6(x) + 8

Subtract 8 from both sides.

6x = 32 - 8

6x = 24

Divide both sides by 6.

x = 4

Carolina is works 4 hours to be paid 32.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.