Which values of c will cause the quadratic equation –x2 + 3x + c = 0 to have no real number solutions? Check all that ap...

a quadratic equation has no real number solutions than the discriminant is less than zero  

D < 0  

(b^2 -4ac) < 0  

(9 -4(-1*c) < 0

(9+4c) < 0

4c < -9

c < -9/4

hope this will help you

Step-by-step explanation:

probably the last option

step-by-step explanation:

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.