Statement Reason
1. EFGH is a parallelogram
1. Given
2. EF | GH and HE FG
2.
3. ZEFH ZGHF and
ZEHF ZGFH
3
3.
4. FG FG
5. AEFH AGHF
S.
6. EF
GH and HE - FG+ 6.

Areflection of shape i across the y-axis, followed by a , and then a translation left 6 units and down 4 units confirms congruence between shape i and shape ii. alternatively, a of shape ii about the origin, followed by a reflection across the y-axis, and then a translation right 4 units and up 6 units confirms congruence between shape ii and shape i.