What is the slope line perpendicular to the equation 4x+3y=9

m=3/4

Step-by-step explanation:

first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)

we have the equation 4x+3y=9

subtract 4x from both sides

3y=-4x+9

divide by 3

y=-4/3x+3

perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1

so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1

(m is the slope value)

-4/3m=-1

multiply by -3/4

m=3/4

therefore the slope of the perpendicular line is 3/4

hope this helps!! :)

b. 1.25 hr

step-by-step explanation:

if you have a constant speed of 60 mph, then you have a ratio between 60 mi. to 1 hr. dividing both sides by 60 we get the ratio

1 mi. to

then mult. both sides by 75 we get the ratio

75 mi. to

simplifying we get

75 mi. to

or 1.25 hr.