The ages of members of a bowling league are normally distributed with a mean of 43 years and a standard deviation of 4 years. there are 200 members in the league.

About how many members are expected to be between 35 years old and 51 years old?

136
160
183
190​

35  is  2 standard deviations BELOW the mean of 43

51  is  2 standard deviations ABOVE the mean of 43

find z - score for + 2 S.D.     then subtract the z-score for  - 2 S.D.    

  This is the percentage ( in decimal form)    of 200 members between the ages of 35 and 51        Can you finish?

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

i dont know men

step-by-step explanation: