the slope of the tangent to the curve y=e^(x-1) is equal to one. Find the x-value when gradient of the tangent is equal to 1​

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*