The O'Brien family has 4 kids, 3 boys and 1 girl. Suppose that for each birth, the probability of a boy birth is 1/2, and the probability of a girl birth is also 1/2. What is the fractional probability of having 3 boys and 1 girl, in any order, in a family's first 4 births?

3

Step-by-step explanation:

1/4

Step-by-step explanation:

It would be 1/4 because for the first child, the probability of it being a boy is 1/2, and for the second one, it would have 1/2 as well. There are 4 ways the first two children could have been:

1. boy boy - it is 1/4 of the options.

2. boy girl

3. girl boy

4. girl girl

Another way to solve it is by multiplying 1/2 by 1/2.

Step-by-step explanation:

(x) - (y) = (1 + 4i)

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week