Let R be the triangular region in the first quadrant with vertices at. Points (0,0), (h,0), and (h, r), where r and h are positive constants

answer: y=0 if that is what u r looking for

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4

the awnser is visionary