Mathematics, 05.05.2021 05:30 1tzM3
Review graph I and graph II.
On a coordinate plane, a parabola labeled Graph 2 opens down. It goes through (negative 2, 0), has a vertex at (negative 2, 7), goes through open circle (negative 4, 5), and goes through (negative 6, 0).
On a coordinate plane, a parabola labeled Graph 1 opens down. It goes through (negative 2, 0), has a vertex at (negative 2, 7), goes through open circle (negative 4, 5), and goes through (negative 6, 0). An open circle is at (negative 4, 8).
Which statement compares the limit as x approaches –4 for the two graphs?
In both graph I and graph II, the limit is 5.
In both graph I and graph II, the limit does not exist.
In graph I, the limit does not exist, but in graph II, the limit is 5.
In graph I, the limit is 8, but in graph II, the limit does not exist.
Answers: 3
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Divide. write in the simplest form. 4 1/6 divided by 10
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With this question substitute t=3 and t=5 to determine if the two expressions are equivalent. 4(t + 3) 4t+12 which statements are true? check all that apply. a. the value of both expressions when t =5 is 32. b. the two expressions are not equivalent. c. the value of both expressions when t=3 is 15. d. the value of both expressions when t=5 is 23. e. the two expressions are equivalent. f. the value of both expressions when t=3 is 24.
Answers: 3
Review graph I and graph II.
On a coordinate plane, a parabola labeled Graph 2 opens down. It goes...
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