Mathematics, 05.05.2021 18:50 jerry22591
1. The z value for a 81.98% confidence interval estimation is
2. The t value for a 90% confidence interval estimation with 15 degrees of freedom is
3. A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the customers in the sample stayed in the restaurant was 45 minutes with a standard deviation of 14 minutes.
With a .9356 probability (93.56% confidence) what is the margin of error?
Answers: 1
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1. The z value for a 81.98% confidence interval estimation is
2. The t value for a 90% confidence...
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