Consider a triangle ABC like the one below. Suppose that B = 37°, C = 64°, and a = 59. (The figure is not drawn to scale.) Solve the triangle.

An arrow is shot vertically upward at a rate of 180ft/s. use the projectile formula h=−16t2+v0t to determine at what time(s), in seconds, the arrow is at a height of 420ft. round your answer(s) to the nearest tenth of a second.

How to do this , and can some one explain

How do i simply this expression (quadratic formula basis) on a ti-84 or normal calculator?