A person is standing on the sidewalk 800 feet from the base of a building. The height of the building is 250 ft. The person looks up and sees a flag on the building's roof. To the nearest degree what is the angle of elevation to the top of the building from the point on the ground where the person is standing?

A person is standing on the sidewalk 800 feet from the base of a building. The height of the building is 250 ft. The person looks up and sees a flag on the building's roof. To the nearest degree what is the angle of elevation to the top of the building from the point on the ground where the person is standing?

Step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

529 and 531

step-by-step explanation: