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Mathematics, 06.05.2021 03:50 giavanleer14

Prove: An odd times an odd equals an odd.
(2m + 1)(2n + 1) = [ ? ]mn + ]m +[ ]n + [ ]
= 2([ ]mn + m + 1 + 1
= odd


Prove: An odd times an odd equals an

odd.
(2m + 1)(2n + 1) = [ ? ]mn + ]m +[ ]n + [ ]
= 2([ ]mn +

ansver
Answers: 2

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Prove: An odd times an odd equals an odd.
(2m + 1)(2n + 1) = [ ? ]mn + ]m +[ ]n + [ ]
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