Two stores opened on the same day. At the end of the first week, the number of shoppers to each store was 30. For the first 6 weeks, the number of shoppers to each store increased according to the following rules. PLEASE HURRY

Store A: The number of shoppers tripled each week.

Store B: The number of shoppers increased by 100 each week.

If the trend continues, will one store eventually exceed the other store in the number of shoppers?

A.

Store A will exceed Store B in 2 weeks.

B.

Store B will exceed Store A in 2 weeks.

C.

Store A will exceed Store B in 3 weeks.

D.

Store B will exceed Store A in 3 weeks.

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the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

look at the picture i have filled out a table for it. hope this .