You want to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter. What is the probability that a randomly chosen code starts with M and ends with E? A. 0.01
B. 0.02
C. 0.05
D. 0.10

Prob( picking an M first) =  1/5

Now we require the sequence not e, not e, not e .

=  3/4 * 2/3* *1/2  

So required probability = 1/5 * 3/4 * 2/3 * 1/2  = 6/120  = 1/20

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

answer: i think one of the answer is $150 and $300?

step-by-step explanation: