Help plz Two ships are sailing in the fog and are being monitored at ten-second intervals by R. J. Sampson. As they enter his rada
screen at 6:00 AM, the Minnow is 1000 meters above the lower left corner of the screen (which will be referred to as the
Origin). The Lollipop is 8000 meters directly to the right of the origin
After ten seconds, the Minnow is 40 meters east and 10 meters north of its original position
After ten seconds, the Lollipop is 30 meters west and 20 meters north of its original position
You may assume that the two ships maintain their courses and speed throughout the problem. Do the ships collide?

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

step-by-step explanation:

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)