PLZ HELP IF YOU PUT A LINK I WILL REPORT YOU YALL BEEN WASTING MY POINTS LATELY I HATE IT SO NO SNEAKY LINK OR NON ANSWER OR U WILL BE REPORTED. PLZ HELP IF YOU PUT A LINK I WILL REPORT YOU YALL BEEN WASTING MY POINTS LATELY I HATE IT SO NO SNEAKY LINK OR NON ANSWER OR U WILL BE REPORTED.

I PUT IT TWICE BECAUSE U PEOPLE DONT GET IT
NO LINKS OR NON ANSWERS
DONT MAKE ME GO CRAZY

step-by-step explanation:

6.5

step-by-step explanation:

you said it was in the question

~courtney

asadsadsad

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)